A conducting circular loop of resistance 20Ω and cross-sectional area 20 × 1 0 − 2 m 2 is placed perpendicular to a spatially uniform magnetic field B, which varies with time tas B = 2 sin ( 50 π t )

Question

A conducting circular loop of resistance $20Ω$ and cross-sectional area $20 \times 1 0^{- 2} m^{2}$ is placed perpendicular to a spatially uniform magnetic field B, which varies with time tas $B = 2 sin (50 π t)$ T. Find the net charge flowing through the loop in $20 ms$ starting from $t = 0$

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Answer:

C

Solution:

Hint : $Δ q = \frac{Δ φ}{R} = \frac{φ _{2} - φ _{1}}{R} = 0, Δ q = 0 [φ_{1} = φ_{2} = 0$ at $t = 0$ and $t = 20 ms]$

TestHub · Accepted Answer

Hint : Δ q = R Δ φ ​ = R φ 2 ​ − φ 1 ​ ​ = 0 , Δ q = 0 [ φ 1 ​ = φ 2 ​ = 0 at t = 0 and t = 20 ms ]

Physics - Magnetism Question with Solution | TestHub

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