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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic ForceEasy2 minPYQ_2020

PhysicsEasysingle choice

A charged particle is moving in a uniform magnetic field in a circular path. The energy of the particle is doubled. The initial radius of the new circular path will be

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Answer:

Solution:

$\begin{array}{l} r = \frac{m v}{q B}, r^{2} = \frac{m^{2} v^{2}}{q^{4} B^{2}} = \frac{2 m (KE)}{q^{2} B^{2}} \\ r \propto \sqrt{K E} \Rightarrow \frac{r_{2}}{r_{1}} = \sqrt{\frac{K E_{2}}{K E_{1}}} \end{array}$

$\Rightarrow r_{2} = \sqrt{\frac{2 {KE}_{1}}{{KE}_{1}}} R \Rightarrow r_{2} = \sqrt{2} R$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Magnetic Force

⏱ 2mℹ️ Source: PYQ_2020

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