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PhysicsMagnetismMagnetic Dipole & MomentMedium2 minPYQ_2020
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A circular coil has moment of inertia0.8 kg m2around any diameter and is carrying current to produce a magnetic moment of20 Am2. The coil is kept initially in a vertical position and it can rotate freely around a horizontal diameter. When a uniform magnetic field of4 Tis applied along the vertical, it starts rotating around its horizontal diameter. The angular speed the coil acquires after rotating by60owill be :

Options:

Answer:
A
Solution:

From energy conservation 

122=Un-Ut

   =-MBcos60°-(-MB)

MB2=122

20×42=12(08)m2

100=ω2

ω=10rad 

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic Dipole & Moment
2mℹ️ Source: PYQ_2020

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