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PhysicsMagnetismMagnetic Dipole & MomentEasy2 minPYQ_2020
PhysicsEasysingle choice

An iron rod of volume10-3 m3and relative permeability1000is placed as core in a solenoid with10 turns cm-1. If a current of0.5 Ais passed through the solenoid, then the magnetic moment of the rod will be :

Options:

Answer:
B
Solution:

Given,

Volume of iron rod is, V=10-3 m3

Relative permeability, μr=1000

No of turns per unit length of solenoid is, n=Nl=10 turns cm-1=1000 turns m-1

Current through the solenoid is, i=0.5 A

Magnetic moment of an iron core solenoid is given by,

M=(μr-1) NiA

M=μr-1NiVl=μr-1NliV

M=1000-1×1000×0.5×10-3

M=499.5500 A m2

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic Dipole & Moment
2mℹ️ Source: PYQ_2020

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