Start Free Mock LoginAlready registered? Login here

Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMotion analysis in electric & magnetic fieldEasy2 minPYQ_2020

PhysicsEasysingle choice

When a magnet is suspended at an angle $30 °$ from the magnetic meridian, it makes an angle $45^{o}$ with horizontal. What will be the actual angle of dip?

Options:

Answer:

Solution:

$\tan^{- 1} (\frac{\sqrt{3}}{2})$

Given deviation from magnetic meridian $α = 30^{o}$ and apparent dip $ϕ^{'} = 45 °$

Then, ${\tan ϕ}^{'} = \frac{\tan ϕ}{\cos α}$

$\tan 45^{o} = \frac{\tan ϕ}{\cos 30^{o}}$

$ϕ = \tan^{- 1} (\frac{\sqrt{3}}{2})$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Motion analysis in electric & magnetic field

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...