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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawEasy2 minPYQ_2020

PhysicsEasysingle choice

Three rings, each having equal radius $R$ , are placed mutually perpendicular to each other and each having its centre at the origin of the coordinate system. If a current $I$ is flowing through each ring, then the magnitude of the magnetic field at the common centre is

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Answer:

Solution:

$\vec{B} = B_{x} \hat{i} + B_{y} \hat{j} + B_{z} \hat{k} \Rightarrow B = \sqrt{B_{x}^{2} + B_{y}^{2} + B_{z}^{2}}$

Since $B_{x} = B_{y} = B_{z}$ so $B = \sqrt{3} B_{0}$

$B = \sqrt{3} \frac{μ_{0} I}{2 R}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2020

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