Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawEasy2 minPYQ_2020

PhysicsEasysingle choice

A loop $ABCD$ has current $I = 10 A$ , as shown in the figure. $AD$ and $BC$ are circular arcs with centre at $O$ , for both. The magnetic field at point $O$ is

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Answer:

Solution:

Magnetic field due to $AB$ and $CD$ are zero at $O$

Magnetic field due to $BC$

$B_{B C} = \frac{μ_{0}}{4 π} \frac{10}{3 \times 10^{- 2}} \times \frac{π}{4}$ (outwards)

Simplifying field due to $DA$

$B_{S P} = \frac{μ_{0}}{4 π} \frac{10}{5 \times 10^{- 2}} \times \frac{π}{4}$ (inwards)

Net field $B = \frac{μ_{o}}{4 π} \frac{10 π}{4 \times 10^{- 2}} (\frac{1}{3} - \frac{1}{5})$

$= 1 .0 \times 10^{- 5} T$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2020

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