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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMotion analysis in electric & magnetic fieldEasy2 minPYQ_2020

PhysicsEasysingle choice

The horizontal component of the earth's magnetic field at any place is $0.36 \times 1 0^{- 4} Wb m^{- 2}$ . If the angle of dip at that place is $60 °$ then the value of the vertical component of earth's magnetic field will be (in $W b m^{- 2}$ )

Options:

Answer:

Solution:

Given,

$B_{H} = 0.36 \times 1 0^{- 4} W b m^{- 2}$

Angle of dip

$\tan θ = \frac{B_{V}}{B_{H}}$

$\tan 60 ° = \frac{B_{V}}{0.36 \times 1 0^{- 4}}$

$B_{V} = (0.36) (\sqrt{3}) \times 1 0^{- 4}$

$B_{V} = 0.62 \times 1 0^{- 4} W b m^{- 2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Motion analysis in electric & magnetic field

⏱ 2mℹ️ Source: PYQ_2020

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