Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic properties of matterEasy2 minPYQ_2020

PhysicsEasysingle choice

A solenoid $30 cm$ long is made by winding $2000$ loops of wire on an iron rod whose cross-section is $1 .5 {cm}^{2}$ . If the relative permeability of the iron makes it $600$ . What is the self-inductance of the solenoid?

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Answer:

Solution:

Self-inductance of the solenoid

$L = \frac{μ_{0} μ_{r} N^{2} A}{l}$

$= \frac{600 \times 4 π \times 10^{- 7} \times {(2000)}^{2} \times (1.5) \times 10^{- 4}}{0.3}$

$= 1 .5 H$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Magnetic properties of matter

⏱ 2mℹ️ Source: PYQ_2020

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