Four very long wires are arranged as shown in the figure, so that their cross-section forms a square, with connections at the ends so that current $I$ flow through all four wires. The length of each side, of the formed square cross-section, is $b$ . The magnetic field at the central point $P$ (centre of the square) is

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Answer:

B

Solution:

net field $= 2 \sqrt{2} B$

where $B = \frac{μ_{0} I}{2 π (\frac{b \sqrt{2}}{2})}$

$∴$ net field $= \frac{2 μ_{0} I}{π b}$

TestHub · Accepted Answer

net field = 2 2 B where B = μ 0 I 2 π ( b 2 2 ) ∴ net field = 2 μ 0 I π b

Physics - Magnetism Question with Solution | TestHub

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