Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMotion analysis in electric & magnetic fieldHard2 minPYQ_2020

PhysicsHardsingle choice

A proton accelerated by a potential difference $V,$ moves through a transverse magnetic field $B$ as shown in the figure. Then the angle $θ$ through which the proton deviates from the initial direction of its motion is

Options:

Answer:

Solution:

$B q v = \frac{m v^{2}}{r}$

$\frac{1}{2} m v^{2} = V q$

And $\sin θ = \frac{d}{r}$

$r = \frac{m v}{q B} = \frac{m}{q B} \sqrt{\frac{2 V q}{m}}$

$\sin θ = d B \sqrt{\frac{q}{2 m V}}$

$θ = \sin^{- 1} (d B \sqrt{\frac{q}{2 m V}})$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Motion analysis in electric & magnetic field

⏱ 2mℹ️ Source: PYQ_2020

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