Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawEasy2 minPYQ_2020

PhysicsEasysingle choice

A wire in the form of a square of side $a$ carries a current $i$ . Then, the magnetic induction at the centre of the square wire is (magnetic permeability of free space $= μ_{0}$ ).

Options:

Answer:

Solution:

Magnetic field due to one side of the square at centre O.

$B_{1} = \frac{μ_{0}}{4 π} . \frac{2 i \sin 45^{o}}{\frac{a}{2}}$

$\Rightarrow$ $B_{1} = \frac{μ_{0}}{4 π} . \frac{2 \sqrt{2} i}{a}$

Hence, magnetic field at centre due to all sides

$B_{n e t} = 4 B_{1} = \frac{μ_{0} (2 \sqrt{2} i)}{π a}$

Subject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2020

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