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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

The time period of oscillation of a magnet is $2 \sec$ . When it is magnetised so that its pole strength is $4$ times, its period will be

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Answer:

Solution:

Time period of oscillation of a magnet is,

$T = 2 π \sqrt{\frac{I}{MB}}$

$\frac{T_{2}}{T_{1}} = \sqrt{\frac{M_{1}}{M_{2}}}$

$\frac{T_{2}}{2} = \sqrt{\frac{M}{4 M}}$

$T_{2} = 1 \sec$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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