Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A small magnet of dipole moment $M$ is kept on the arm of a deflection magnetometer set in $\tan A$ position at a distance of $0.2 m$ . If the deflection is $60 °,$ find the value of $M (B_{H} = 0.4 \times 10^{- 4} T)$

Options:

Answer:

Solution:

$∵ B = B_{H} \tan θ$

Or $\frac{μ_{0}}{4 π} . \frac{2 M}{r^{3}} = 0.4 \times 10^{- 4} \tan 60 °$

$∴ \frac{μ_{0} M}{2 π {(0.2)}^{3}} = 0.4 \times 10^{- 4} \tan 60 °$

$M = \frac{0.4 \times 4 π \times {(0.2)}^{3} \times 10^{- 4} \times \sqrt{3}}{2 \times μ_{0}}$

$= \frac{0.00277 \times 10^{- 4}}{10^{- 7}}$

$∴ M = 2.77 A m^{2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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