Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic ForceMedium2 minPYQ_2020

PhysicsMediumsingle choice

A block of mass $m$ and charge $q$ is released on a long smooth inclined plane. Magnetic field $B$ is constant, uniform and out of the plane of the paper as shown. Find the time from the start when blocking lose contact with the surface.

Options:

Answer:

Solution:

Block will lose contact with surface when force due to magnetic field will become equal to $mgcosθ$

$qvB = mgcosθ$

$v = \frac{mgcosθ}{qB} = u + at$ ( along inclined plane )

$v = \frac{mgcosθ}{qB} = (g sin θ) t$

$t = \frac{m cot θ}{qB}$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic Force

⏱ 2mℹ️ Source: PYQ_2020

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