Under the influence of a uniform magnetic field a charged particle is moving in a circle of radius R with constant speed v . The time period of the motion

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TestHub · Accepted Answer

When magnetic field is perpendicular to motion of charged particle, then

Centripetal force = magnetic force

$i e, \frac{m v^{2}}{R} = B q v$

or $R = \frac{m v}{B q}$

Further, time period of the motion

$T = \frac{2 π R}{v} = \frac{2 π (\frac{m v}{B q})}{v}$

or $T = \frac{2 π m}{B q}$

It is independent of both $R a n d v .$

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