Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic ForceEasy2 minPYQ_2020
PhysicsEasysingle choice

A proton moves with a speed of5.0×106 m s-1along thex-axis. It enters a region where there is a magnetic field of magnitude2.0Tdirected at an angle of30°to thex-axis and lying in thexy-plane. The magnitude of the magnetic force on the proton is

Options:

Answer:
C
Solution:

Given, The speed of proton,

v=5.0×106 m s-1

The magnetic field,B=2.0 T

Angleθ=30o

Charge on the proton,q=1.6×10-19 C

When the proton enters in magnitude field, it experiences a magnetic force

F=qv×B

F=qvBsinθ

F=1.6×10-19×5×106×2×sin30°

=8.0×10-13  N

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic Force
2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...