Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic Dipole & MomentEasy2 minPYQ_2020

PhysicsEasysingle choice

Two short bar magnets with magnetic moments $400 ab - A$ $c m^{2}$ and $800 ab - A$ $c m^{2} a r e$ placed with their axis in the same straight line with similar poles facing each other and with their centres at $20 cm$ from each other. Then the force of repulsion is

Options:

Answer:

Solution:

$F = \frac{μ_{0}}{4 π} . \frac{6 M_{1} M_{2}}{r^{4}} = \frac{6 M_{1} M_{2}}{r^{4}}$

$[I n C G S s y s t e m, \frac{μ_{0}}{4 π} = 1]$

$= \frac{6 \times 800 \times 400}{20 \times 20 \times 20 \times 20} =$ $12 dyne$ .

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Magnetic Dipole & Moment

⏱ 2mℹ️ Source: PYQ_2020

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