Physics - Magnetism Question with Solution | TestHub

Given, magnetising field, H = 5000 A/m
Magnetic flux,$\varphi =4\times {10}^{-5}Wb$
Cross-sectional area, A = 0.4$c{m}^2=4\times {10}^{-5}{m}^2$
$\therefore$Permeability of rod,
$\mu =\frac{B}{H}=\frac{\varphi }{AH}\left[\therefore \varphi =BA\Rightarrow B=\frac{\varphi }{A}\right]$
$=\frac{4\times {10}^{-5}}{4\times {10}^{-5}\times 5000}=2\times \frac{{10}^{-4}Wb}{A}-m$