Physics - Magnetism Question with Solution | TestHub

$\begin{array}{rl}& \vec{F}=q\vec{E}+q(\vec{v}\times \vec{B})\\ & \vec{F}=1.6\times 10^{-19}\times 10\hat{i}\times 10^{-6}+1.6\times 10^{-19}\\ & [(2\hat{i})\times (\hat{i}+3\hat{j}+4\hat{k})]\times 10^{-6}\\ & \vec{F}=1.6\times 10^{-19}[10\hat{i}+6\hat{k}-8\hat{j}]\times 10^{-6}\mathrm{N}\\ & \vec{a}=1.6\times 10^{-19}[10\hat{i}-8\hat{j}+6\hat{k}]\times 10^{-6}/1.6\times 10^{-27}\mathrm{m}{\mathrm{s}}^{-2}\\ & a=|\vec{a}|=100\sqrt{200}=1.41\times 1000\approx 1400\mathrm{m}{\mathrm{s}}^{-2}\end{array}$