Physics - Magnetism Question with Solution | TestHub

Net current due to all wires,
$i_{net}=i_1+i_2+i_3+i_4+i_5+i_6$
$i_{net}=10+13+10+7-12+18=20A$
We know, magnetic field due to an infinitely long straight conductor at a perpendicular distance r from it is given by
$B=\frac{{\mu }_{0}i}{2\pi r}=\frac{{\mu }_0{i}_{net}}{2\pi r}$
where,$i$= current in wire
and$r$= perpendicular distance.
$=\frac{4\pi \times {10}^{-7}\times 20}{2\pi \times 10\times {10}^{-2}}=4\times {10}^{-5}$
$B=40\mu T$