A paramagnetic substance of susceptibility 3 × 1 0 − 4 is placed in a magnetising field of 4 × 1 0 − 4 A m − 1 . Then the intensity of magnetisation in the units of A m − 1 is

I = χH = ( 4 × 1 0 − 4 ) × ( 3 × 1 0 − 4 ) = 12 × 1 0 − 8 A m − 1

Start Free Mock LoginAlready registered? Login here

Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismProperties of magnetEasy2 minPYQ_2018

PhysicsEasysingle choice

A paramagnetic substance of susceptibility $3 \times 1 0^{- 4}$ is placed in a magnetising field of $4 \times 1 0^{- 4} A m^{- 1}$ . Then the intensity of magnetisation in the units of $A m^{- 1}$ is

Options:

Answer:

Solution:

$I = χH = (4 \times 1 0^{- 4}) \times (3 \times 1 0^{- 4}) = 12 \times 1 0^{- 8} A m^{- 1}$

Stream:AIIMSSubject:PhysicsTopic:MagnetismSubtopic:Properties of magnet

⏱ 2mℹ️ Source: PYQ_2018

Doubts & Discussion

Loading discussions...