Physics - Magnetism Question with Solution | TestHub

The necessary centripetal force, to move in a circular path is provided by the Coulomb's force. $$\begin{array}{r}\frac{m_1{v}^2}{\gamma }=\frac{1}{4\pi {ϵ}_0}\cdot \frac{q_1{q}_2}{r^2}\\ v=\sqrt{\frac{1}{4\pi {ϵ}_0}\cdot \frac{q_1{q}_2}{r{m}_1}}\end{array}$$ We know, $v=r\omega$ $$\omega =\frac{2\pi }{T}$$ $$\begin{array}{l}T=\frac{2\pi }{\omega }\\ =\frac{2\pi \cdot r}{v}\end{array}$$ Substitution the value of $v$ $T=\frac{2\pi r}{\sqrt{\frac{q_1\cdot q_2}{4\pi {\epsilon }_{0}R\cdot m_1}}}$ $T=\sqrt{\frac{4{\pi }^2{r}^2\times 4\pi {\epsilon }_0\cdot r\cdot m_1}{q{q}_2}}$ $T=\sqrt{\frac{16{\pi }^3{\epsilon }_0{r}^3\cdot m_1}{q_1\cdot q_2}}$ None of the given options is correct. Both the charges are positive or both negative. (Sino answers have the product $q{A}_2$ inside square loy Therefore, circular motion is not possible. The statement of question is wrong. Either $q_1$ or should be negative.