A Conductor (shown in the figure) carrying constant current I is kept in the x - y plane in a uniform magnetic field B → . If F is the magnitude of the total magnetic force acting on the conductor, then the correct statement(s) is (are)

F → = I D i s p l a c e m e n t → × B → As magnetic field is uniform F → = I 2 L + 2 R i ^ × B → When B → is along y or z axis F ∝ L + R When B → is along x -axis F = 0

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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic ForceMedium2 minPYQ_2015

PhysicsMediummultiple choice

A Conductor (shown in the figure) carrying constant current $I$ is kept in the $x$ - $y$ plane in a uniform magnetic field $\vec{B}$ . If $F$ is the magnitude of the total magnetic force acting on the conductor, then the correct statement(s) is (are)

Options:(select one or more)

Answer:

A, B, C

Solution:

$\vec{F} = I (\vec{D i s p l a c e m e n t}) \times \vec{B}$
As magnetic field is uniform
$\vec{F} = I (2 L + 2 R) \hat{i} \times \vec{B}$
When $\vec{B}$ is along $y$ or $z$ axis
$F \propto (L + R)$
When $\vec{B}$ is along $x$ -axis
$F = 0$

Stream:JEE_ADVSubject:PhysicsTopic:MagnetismSubtopic:Magnetic Force

⏱ 2mℹ️ Source: PYQ_2015

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