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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismProperties of magnetEasy2 minPYQ_2014

PhysicsEasysingle choice

If a magnet is suspended at angle $3 0^{\circ}$ to the magnet meridian, the dip of needle makes angle of $4 5^{\circ}$ with the horizontal, the real dip is

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Answer:

Solution:

Here, $tan δ^{'} = \frac{t a n δ}{c o s θ} = \frac{t a n 4 5 ^{\circ}}{c o s 3 0 ^{\circ}}$ $tan δ = \frac{1}{3 /2} = \frac{2}{3}$ or $δ = tan^{- 1} (\frac{2}{3})$

Stream:VITEEESubject:PhysicsTopic:MagnetismSubtopic:Properties of magnet

⏱ 2mℹ️ Source: PYQ_2014

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