If the work done in turning a magnet of magnetic moment M by an angle of 9 0 ∘ from the magnetic meridian is n times the corresponding work done to turn it through an angle of 6 0 ∘ , then the value of n is

Wehave, W = − MB ( cos θ 2 − cos θ 1 ) So, W 1 = − MB ( cos 9 0 ∘ − cos 0 ∘ ) = MB and W 2 = − MB ( cos 6 0 ∘ − cos 0 ∘ ) = 2 1 MB As W 1 = n W 2 ∴ n = W 2 W 1 = 2 1 MB MB = 2

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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismProperties of magnetMedium2 minPYQ_2013

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If the work done in turning a magnet of magnetic moment $M$ by an angle of $9 0^{\circ}$ from the magnetic meridian is n times the corresponding work done to turn it through an angle of $6 0^{\circ}$ , then the value of $n$ is

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Wehave, $W = - MB (cos θ_{2} - cos θ_{1})$ So, $W_{1} = - MB (cos 9 0^{\circ} - cos 0^{\circ}) = MB$ and $W_{2} = - MB (cos 6 0^{\circ} - cos 0^{\circ}) = \frac{1}{2} MB$ As $W_{1} = n W_{2}$ $∴ n = \frac{W _{1}}{W _{2}} = \frac{MB}{\frac{1}{2} MB} = 2$

Stream:VITEEESubject:PhysicsTopic:MagnetismSubtopic:Properties of magnet

⏱ 2mℹ️ Source: PYQ_2013

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