Physics - Magnetism Question with Solution | TestHub

Since axes are perpendicular so mid point lies on axial line of one magnet and on equitorial line of other magnet $\therefore {\mathrm{B}}_1=\frac{{\mu }_0}{4\pi }\frac{2\mathrm{M}}{{\mathrm{d}}^3}=\frac{10^{-7}\times 2\times 1}{1^3}=2\times 10^{-7}\mathrm{T}$ and ${\mathrm{B}}_2=\frac{{\mu }_0}{4\pi }\frac{\mathrm{M}}{{\mathrm{d}}^3}=\frac{10^{-7}\times 1}{1^3}=10^{-7}\mathrm{T}$ As ${\mathrm{B}}_1\perp {\mathrm{B}}_2$ $\therefore$ Resultant magnetic field $=\sqrt{{\mathrm{B}}_1^2+{\mathrm{B}}_2^2}=\sqrt{5}\times 10^{-7}\mathrm{T}$