Magnetic moment of bar magnet is M . The work done to turn the magnet by 9 0 ∘ of magnet in direction of magnetic field B will be

Work done, W = MB ( 1 − cos θ ) θ = 9 0 ∘ W = MB

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Magnetic moment of bar magnet is $M$ . The work done to turn the magnet by $9 0^{\circ}$ of magnet in direction of magnetic field $B$ will be

Answer:

Solution:

Work done, $W = MB (1 - cos θ)$ $θ = 9 0^{\circ}$ $W = MB$

Stream:BITSATSubject:PhysicsTopic:MagnetismSubtopic:Magnetic Dipole & Moment

⏱ 2mℹ️ Source: PYQ_2012

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