A Zener diode has a contact potential of 1 V in the absence of biasing. It undergoes Zener breakdown for an electric field of 1 0 6 V / m at the depletion region of p − n junction. If the width of the

Question

A Zener diode has a contact potential of 1 V in the absence of biasing. It undergoes Zener breakdown for an electric field of 1 0 6 V / m at the depletion region of p − n junction. If the width of the depletion region is 2.5 μ m , what should be the reverse biased potential for the Zener breakdown to occur ?

TestHub · Accepted Answer

Here, electricfield, E = 1 0 6 V / m width of depletion region, d = 2.5 μ m = 2.5 × 1 0 − 6 m ∴ Potential required for breakdown ( V ) = Ed = ( 1 0 6 × 2.5 × 1 0 − 6 ) V = 2.5 V Contact Potential = 1.0 V ∴ Reverse biased potential for zener breakdown = ( 2.5 − 1.0 ) V = 1.5 V

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