The magnetic field due to a current carrying circular loop of radius 3 cm at a point on the axis at a distance of 4 cm from the centre is 54 μ T . What will be its value at the centre of the Loop?

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Using formula B = 2 ( R 2 + X 2 ) 3/2 μ 0 II ​ ​ , we get 54 = 2 [ ( 3 ) 2 + ( 4 ) 2 ] 3/2 μ 0 ​ i ( 3 ) 2 ​ At the centre of the coil, X = 0 and B = 2 ( 3 ) μ 0 ​ i ​ Using equation (i) B = ( 3 ) 2 × 3 54 × 5 3 ​ ⇒ B = 250 μ T .

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