Two balls are projected simultaneously from the top of a tall building, one vertically upward and other vertical downwards with the same speed of $60 m / s$ . Then time interval between the balls striking the ground is :-
Options:
Answer:
C
Solution:
$t = \frac{2 u}{g} = \frac{2 \times 60}{10} = 12 sec$

Question

Two balls are projected simultaneously from the top of a tall building, one vertically upward and other vertical downwards with the same speed of $60 m / s$ . Then time interval between the balls striking the ground is :-

Options:

Answer:

C

Solution:

$t = \frac{2 u}{g} = \frac{2 \times 60}{10} = 12 sec$

TestHub · Accepted Answer

t = g 2 u ​ = 10 2 × 60 ​ = 12 sec

Physics - Kinematics Question with Solution | TestHub

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