If the velocity v of a particle moving along a straight line decreases linearly with its displacement s from $20 ms^{- 1}$ to a value approaching zero at $s = 30 m$ , then acceleration of the particle at $s = 15 m$ is

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​ a = v dx dv ​ ⇒ a = 10 ( 3 − 2 ​ ) = − 3 20 ​ m / s 2 ​ dx dv ​ slope of ’v’ v/s ’s’ is − 3 20 ​ ​ Velocity of this instant is 10

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