The horizontal and vertical displacements of a projectile at time ' t ' are x = 3 t and y = 4 t − 4.9 t 2 respectively where x and y are in meter and t is in second. Initial speed of the pro

Question

The horizontal and vertical displacements of a projectile at time ' t ' are $x = 3 t$ and $y = 4 t - 4.9 t^{2}$ respectively where $x$ and $y$ are in meter and $t$ is in second. Initial speed of the projectile in $m / s$ is :-

Options:

Answer:

A

Solution:

$x = 3 t$

$y = 4 t - 4.9 t^{2}$

$u cos θ = 3$

$u sin θ = 4$

$u = 5$

TestHub · Accepted Answer

x = 3 t y = 4 t − 4.9 t 2 u cos θ = 3 u sin θ = 4 u = 5

Physics - Kinematics Question with Solution | TestHub

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