A bus is beginning to move with an acceleration of 1 m / sec 2 . A boy who is 48 m behind the bus starts running at 10 m / sec . The times at which the boy can catch the bus will be-

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Let the police jeep catch the thief in time $t$ . Then:

$1000 = 20 t \Rightarrow t = 50 sec$

$1000 = 15 (t + Δ t) \Rightarrow 1000 = 15 (50 + Δ t)$

$1000 = 750 + 15Δ t \Rightarrow 250 = 15Δ t$

$Δ t = \frac{250}{15} = \frac{50}{3} \approx 16.67 sec$

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