A parachutist drops freely from an aeroplane for 10 s before the parachute opens. He then descends with a net retardation of 2.5 m / s 2 . If he bails out of the plane at a height of 2495 m and g = 10

Question

A parachutist drops freely from an aeroplane for 10 s before the parachute opens. He then descends with a net retardation of 2.5 m / s 2 . If he bails out of the plane at a height of 2495 m and g = 10 m / s 2 , his velocity on reaching the ground is:

TestHub · Accepted Answer

In 10 s he falls 2 1 ​ ( 10 ) ( 100 ) = 500 m and reaches v = 100 m/s. The remaining 1995 m: v 2 = 10 0 2 − 2 ( 2.5 ) ( 1995 ) = 10000 − 9975 = 25 , so v = 5 m / s . Option C.

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