Start Free Mock LoginAlready registered? Login here

Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium2 minQB

PhysicsMediumsingle choice

For a particle moving along a straight line, the displacement $x$ depends on time $t$ as $x = A t^{3} + B t^{2} + Ct + D$ . The ratio of its initial velocity to its initial acceleration depends on:

Options:

Answer:

Solution:

$v = \frac{d x}{d t} = 3 A t^{2} + 2 Bt + C$ , so $v (0) = C$ ; $a = \frac{d v}{d t} = 6 A t + 2 B$ , so $a (0) = 2 B$ . The ratio is $\frac{C}{2 B}$ , which depends only on $B$ and $C$ . Option B.

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...