A car 2 m long and 3 m wide is moving at 13 m/s when a bullet hits it in a direction making an angle θ = tan − 1 ( 3/4 ) with the car as seen from the street. The bullet enters one edge of a corner an

Question

A car 2 m long and 3 m wide is moving at 13 m/s when a bullet hits it in a direction making an angle $θ = tan^{- 1} (3/4)$ with the car as seen from the street. The bullet enters one edge of a corner and passes out at the diagonally opposite corner. Neglecting any interaction between the bullet and the car, find the time for the bullet to cross the car:

TestHub · Accepted Answer

Relative to the car, the bullet velocity components are ( v cos θ − 13 ) along and v sin θ across; crossing the diagonal needs ( v cos θ − 13 ) / ( v sin θ ) = 2/3 . With tan θ = 3/4 : v = 32.5 m/s and t = 3/ ( v sin θ ) = 3/19.5 = 0.15 s. Option C.

Physics - Kinematics Question with Solution | TestHub

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