The displacement x of a body varies with time t as x = − 3 2 t 2 + 16 t + 2 . The body will come to rest after:

v = d t d x = − 3 4 t + 16 = 0 gives t = 12 s. Option B.

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The displacement $x$ of a body varies with time $t$ as $x = - \frac{2}{3} t^{2} + 16 t + 2$ . The body will come to rest after:

Answer:

Solution:

$v = \frac{d x}{d t} = - \frac{4}{3} t + 16 = 0$ gives $t = 12$ s. Option B.

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

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