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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DEasy2 minQB

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Passage / Comprehension

A moving particle is acted upon by three forces at different times to bring it to rest. Its velocity versus time graph is given below

The average velocity for the first 12 s is

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Answer:

Solution:

Average velocity for first $12 s = \frac{displacement in first 12 s}{12 s}$ $= \frac{- \frac{1}{2} \times 15 \times 4 + \frac{1}{2} \times 2 \times 10 + 2 \times 10 + ( \frac{20 + 10}{2} ) ( 2 - 4 )}{12} = \frac{60}{12} = 5 ms^{- 1}$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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