Physics - Kinematics Question with Solution | TestHub

Displacement of particle from $\mathrm{t}=0$ to $\mathrm{t}=\frac{\pi }{4}\sec$ is $\frac{{\pi }^2}{8}\left(\frac{\pi }{3}-\frac{\sqrt{3}}{4}\right)\mathrm{m}$

Displacement of particle from $\mathrm{t}=0$ to $\mathrm{t}=\frac{\pi }{4}$ sec is $\frac{{\pi }^3}{32}\mathrm{m}$

Displacement of particle from $\mathrm{t}=0$ to $\frac{\pi }{4}\sec$ is $\frac{\sqrt{3}{\pi }^2}{32}\mathrm{m}$

Magnitude of acceleration of particle first decreases than increases.