A car is moving with a velocity 54 km / hr and then breaks are applied, which provides a deacceleration of 5 m / s 2 . Then the displacement of the car in 10 sec will be :-

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u car ​ = 54 km / hr = 15 m / s , a c a r ​ = − 5 m / s 2 velocity will be zero in time 0 = 15 − 5 t ⇒ t = 3 sec ​ S = 15 × 3 + 2 1 ​ ( − 5 ) × 9 ​ = 22.5 m ​

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