Start Free Mock LoginAlready registered? Login here

Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium2 minQB

PhysicsMediumsingle choice

Three particles start from the origin at the same time, the first with 3 m/s along the positive $x$ -axis, the second with 6 m/s along the negative $y$ -axis. Find the speed of the third particle along the $x = y$ line so that the three always lie in a straight line:

Options:

Answer:

Solution:

The line through $(3 t, 0)$ and $(0, - 6 t)$ is $2 x - y = 6 t$ ; substituting $(v t / 2, v t / 2)$ gives $v t / 2 = 6 t$ , so $v = 62$ m/s. Option B.

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...