A car 2 m long and 3 m wide is moving at 6 m/s when a bullet hits it in a direction making θ = tan − 1 ( 3/4 ) with the car as seen from the street. The bullet enters one corner edge and exits at the

Question

A car 2 m long and 3 m wide is moving at 6 m/s when a bullet hits it in a direction making $θ = tan^{- 1} (3/4)$ with the car as seen from the street. The bullet enters one corner edge and exits at the diagonally opposite corner. The time for the bullet to cross the car is:

Options:

Answer:

A

Solution:

$(v cos θ - 6) / (v sin θ) = 2/3$ with $tan θ = 3/4$ gives $v = 15$ m/s; $t = 3/ (v sin θ) = 3/9 = 0.33$ s. Option A.

TestHub · Accepted Answer

( v cos θ − 6 ) / ( v sin θ ) = 2/3 with tan θ = 3/4 gives v = 15 m/s; t = 3/ ( v sin θ ) = 3/9 = 0.33 s. Option A.

Physics - Kinematics Question with Solution | TestHub

Options:

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