Start Free Mock LoginAlready registered? Login here

Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium2 minQB

PhysicsMediumsingle choice

A person throws balls into the air one after the other at an interval of two seconds. The next ball is thrown when the velocity of the ball thrown earlier is zero. Taking $g = 10 m / s^{2}$ , to what height does each ball rise?

Options:

Answer:

Solution:

The velocity is zero $2$ s after each throw, so $u = 10 (2) = 20$ m/s and $h = \frac{u ^{2}}{2 g} = \frac{400}{20} = 20$ m. Option C.

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...