Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium2 minQB
PhysicsMediummatching list

Each entry of List-I shows a graph of a particle's one-dimensional motion. Match the entries of List-I with entries of List-II.

List-I

List-II

position-time graph

(1) Particle must change its direction during the subsequent motion

speed-time graph

(2) Particle may return to its initial position during subsequent motion

acceleration-time graph

(3) Acceleration vector of a particle must be constant throughout the motion

distance-time graph

(4) Particle come to rest at least once during its motion

-

(5) Initial velocity of particle is zero.

Options:

Answer:
D
Solution:

(P) Position-time parabola: velocity changes sign (direction changes), particle returns to start, acceleration is constant and negative, and at the top - P.

(Q) Speed-time: initial speed non-zero, particle can return, speed becomes zero once - Q.

(R) Acceleration-time: area gives only, so return is possible; acceleration is not constant - R.

(S) Distance-time: distance has no direction, return is possible; slope = speed - S.

Hence option (D).

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D
⏱ 2mℹ️ Source: QB

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