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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics219Medium2 minQB

PhysicsMediumsingle choice

An object is projected with initial velocity 100 m/s at an angle 53° above horizontal from a 80 m high building. The velocity of the ball at half the maximum height from the ground is :-

Options:

Answer:

Solution:

$u_{x} = 60 m / s$ , $u_{y} = 80 m / s$ ; max height = 320 m from projection

At 200 m above ground (120 m above projection): $v_{y}^{2} = 8 0^{2} - 2 \times 10 \times 120$ , so $v_{y} = \pm 2010$

$v = 60 \hat{i} \pm 2010 \hat{j}$

Answer (A)

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:219

⏱ 2mℹ️ Source: QB

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