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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium2 minQB

PhysicsMediumsingle choice

A particle is moving at a speed of 5 m/s along east. After 10 s its velocity changes and becomes 5 m/s along north. What is the average acceleration during this interval:

Options:

Answer:

Solution:

$a = (v_{f} - v_{i}) / t = (5 j - 5 i) /10$ ; its magnitude is $25 + 25 /10 = 1/ 2$ $m / s^{2}$ directed north-west. Option B.

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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