A particle starts moving in the + x direction with initial velocity 10 m / s and a uniform acceleration of magnitude 2 m / s 2 directed in the − x direction. The distance traversed by the particle in

Question

A particle starts moving in the + x direction with initial velocity 10 m / s and a uniform acceleration of magnitude 2 m / s 2 directed in the − x direction. The distance traversed by the particle in 12 seconds is:

TestHub · Accepted Answer

The particle comes to rest at t 1 ​ where 0 = 10 − 2 t 1 ​ , i.e. t 1 ​ = 5 s, having covered s 1 ​ = 10 ( 5 ) − 2 1 ​ ( 2 ) ( 25 ) = 25 m. It then accelerates backwards for 7 s, covering s 2 ​ = 2 1 ​ ( 2 ) ( 49 ) = 49 m. Total distance = 25 + 49 = 74 m. Option D.

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