A projectile of mass 1.50 kg leaves the ground with a kinetic energy of 200 J. Only gravity acts on the projectile after it leaves the ground. At the highest point in its trajectory, its kinetic energ

Question

A projectile of mass 1.50 kg leaves the ground with a kinetic energy of 200 J. Only gravity acts on the projectile after it leaves the ground. At the highest point in its trajectory, its kinetic energy is 100 J . To what vertical height, relative to its launch point, did it rise?

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Answer:

D

Solution:

$U_{i} + K_{i} = U_{f} + K_{f}$

$0 + 200 = 100 + 1.5 \times 10 \times h$

$h = \frac{100}{15} = \frac{20}{3} m$

TestHub · Accepted Answer

U i ​ + K i ​ = U f ​ + K f ​ 0 + 200 = 100 + 1.5 × 10 × h h = 15 100 ​ = 3 20 ​ m

Physics - Kinematics Question with Solution | TestHub

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