Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DEasy2 minQB

PhysicsEasymultiple choice

Position of a particle is given by $x = t^{3} - 3 t^{2} - 6 t + 5$ , where $t$ is the time (in sec.). Than :

Answer:

C, D

Solution:

$v = \frac{dx}{dt} = 3 t^{2} - 6 t - 6$

$a = \frac{dv}{dt} = 6 t - 6$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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